A climber is attached to a vertical rope that has a tension of 455 N. If the climber has a mass of 95 kg, what is the net force on the climber?
The net force on the climber is the difference between the gravitational force acting on the climber and the tension force acting on the rope. The gravitational force is given by: Fg = m*g where m is the mass of the climber and g is the acceleration due to gravity, which is approximately 9.8 m/s^2. Fg = 95 kg * 9.8 m/s^2 Fg = 931 N The tension force acting on the rope is given as 455 N in the upward direction. Therefore, the net force on the climber is: Fnet = Fg - T where T is the tension force acting on the rope. Fnet = 931 N - 455 N Fnet = 476 N Therefore, the net force on the climber is 476 N, acting in the downward direction.